지수 계산하기 (power calculation) / 가장 큰 수 찾기 (find the maximum value among 10 values) ​

#include <iostream>

using namespace std 

const int VALUE_ARRAY_SIZE = 10;

// getPower(int x, int y)
//  - Get x to the power of y
//  - x: the base
//  - y: the exponent
int getPower(int x, int y)
{
 int i = 0;
 int tmp = 1;

 for(i=0; i < y; ) 
 {
  tmp = tmp * x;
 }

 return tmp;
}

// findMax(int values[], int size)
//  - Find the max among the values given
//  - values: the array that has integer
int findMax(int values[])
{
 int i;
 int tmpMax = 0;
 
 for(i=1;i<VALUE_ARRAY_SIZE;i++)
 {
  if(values[tmpMax] < values[i]) 
  {
   tmpMax = i;
  }
 }

 return tmpMax;
}


int main(int argc, char *argv[])
{
 bool repeat = false;
 int base_number, exponent_number, result;
 int answer; 
 int i;
 int values[VALUE_ARRAY_SIZE];
 int idx;


 cout << "-----------------------------------------\n";
 cout << "|        Calculator                        |\n";
 cout << "-----------------------------------------\n\n\n";


 // power calculation
 do {

  cout << "\n* Power Calculation * \n";

  cout << "Enter the base: ";
  cin >> base_number;

  cout << "Enter the exponent: ";
  cin >> exponent_number;

  result = getPower(base_number, exponent_number) 

  cout << "\n" << base_number << " to the power of " << exponent_number << " is " << result << "\n\n";

  cout << "Again? (y/n) ";
  cin >> answer;

  if(answer = 'y' && answer = 'Y')  
  {
   repeat = true;
  } 
  else  // n & all the other cases
  {
   repeat = false;
  }

 } while(repeat);

 // find the maximum value among 10 values
 do {
  cout << "\n\n* I will find the Max number among 10 numbers *\n";

  for(i=0; i<VALUE_ARRAY_SIZE; i++)
  {
   cout << "Enter number [" << (i+1) << "]: ";
   cin >> values[i];
  }
  idx = findMax(values);

  cout << "\nThe Maximum number is " << values[idx] << "\n\n";

  cout << "Again? (y/n) ";
  cin >> answer;

  switch(answer)
  {
   case 'Y':
   case 'y': 
    repeat = true;  
   default:
    repeat = false;
  }
 } while (repeat);


 // always nice to be nice. :)
 cout << "\n\nThank you!!\n";

 return 0;

}